The science of physics is often divided into Classical Physics and Modern Physics. Classical physics works well describing and predicting almost all everyday phenomena. It breaks down when things get too ... . (You can substitute here almost any very large deviation from out everyday experience.)
In classical physics the world is made of matter particles that
behave according to Newton's laws of motion. To use Newton's laws, we need to
know which forces are acting on the particles. The interactions that give rise
to the forces between the particles are represented by fields.
Electric and magnetic fields represent the electromagnetic interactions. If we
know the fields, we know the electric and the magnetic forces acting on charged
particles.
F = Felectric +
Fmagnetic =
qE +
qv × B =
q(E + v × B).
In classical physics our model for the electromagnetic fields is a set of four
equations, called Maxwell's equations.
They let us predict E(r) and B(r) if
we know the charge densities ρ(r) and the current densities j(r)
in some volume V, and we have information about the fields at the boundaries of
V. Maxwell's equations have a broader range of
applicability than Newton's laws. They are relativistically correct and
correctly describe the fields when relative speeds approach the speed of light.
But the classical model for the electromagnetic fields no longer describes
observations correctly on the scale of atoms or elementary particles.
Maxwell's equations (in SI units) are
(1) ∇∙E = ρ/ε0,
(2) ∇×E = -∂B/∂t,
(3) ∇·B = 0,
(4) ∇×B = μ0j + (1/c2)∂E/∂t,
or, in integral form
(1) ∮A E∙dA = Qinside/ε0,Here ρ = charge density, j = current density, ε0 = 8.854*10-12 C2/(Nm2), μ0 = 4π*10-7 N/A2.
Maxwell's equations predict:
-- A charged particle produces an electric field. This electric field exerts a force on other charged particles. Positive charges accelerate in the direction of the field and negative charges accelerate in a direction opposite to the direction of the field.Accelerating charges produce changing electric and magnetic fields. Changing electric fields produce magnetic fields and changing magnetic fields produce electric fields. This interplay between induced electric and magnetic fields leads to propagating electromagnetic waves. Electromagnetic waves can propagate through free space. In classical physics visible light is an electromagnetic wave with a frequency in the range of ~4.3*1014 Hz to ~7.5*1014 Hz.
Visible light makes up just a small part of the full electromagnetic spectrum. Electromagnetic waves with shorter wavelengths and higher frequencies include ultraviolet light, X-rays, and gamma rays. Electromagnetic waves with longer wavelengths and lower frequencies include infrared light, microwaves, and radio and television waves.
| Type of Radiation | Frequency Range (Hz) | Wavelength Range |
|---|---|---|
| gamma-rays | 1020 - 1024 | < 10-12 m |
| x-rays | 1017 - 1020 | 1 nm - 1 pm |
| ultraviolet | 1015 - 1017 | 400 nm - 1 nm |
| visible | 4*1014 - 7.5*1014 | 750 nm - 400 nm |
| near-infrared | 1*1014 - 4*1014 | 2.5 μm - 750 nm |
| infrared | 1013 - 1014 | 25 μm - 2.5 μm |
| microwaves | 3*1011 - 1013 | 1 mm - 25 μm |
| radio waves | < 3*1011 | > 1 mm |

In vacuum, where there are no charge and current densities, Maxwell's
equations lead to the homogeneous wave equation for E and B in
three dimensions.
∇2E -
μ0ε0∂2E/∂t2 =
0, ∇2B -
μ0ε0∂2B/∂t2 =
0 , with μ0ε0 = 1/c2.
This equation has infinitely many solution. But we often concentrate on
sinusoidal plane waves solutions of the form
E(r,t) = Re(E0ei(k∙r - ωt)), B(r,t) = Re(B0ei(k∙r -
ωt)), with ω/k = λf = c.
Here k is the wave number, k =|k|= 2π/λ, and ω = 2π/T = 2πf is the angular
frequency of the wave.
k is the wave vector. k points in the direction of
propagation of the wave.
The wave equation is a linear equation, so the real and the imaginary part of a
solution do not mix, and it is often easier to work with exponential functions
than with trigonometric functions. The solutions expressed in terms of trigonometric functions are
E(r,t) = |E0|cos(k∙r - ωt + φ), B(r,t) = |B0|cos(k∙r -
ωt + φ).
E0 and B0 are complex numbers, E0 = |E0|eiφ,
B0 = |B0|eiφ, φ is called the phase
constant.
Maxwell's equations imply that EM waves in free space are transverse waves.
We have E ⊥ B, E ⊥ k,
B ⊥
k, B = (k/k)×E/c.
The magnetic field of the electromagnetic wave is perpendicular
to the electric field and has magnitude B = E/c in
free space.
For electromagnetic waves in vacuum E and B are
always perpendicular to each other and perpendicular to the direction of
propagation. The direction of propagation is the direction of
E×B.
Because the wave equation is a linear equation, any solution, (spherical waves, wave pulses, etc) can be written as a linear superposition of plane waves with properly chosen directions of propagation, amplitudes, angular frequencies and phase constants, as long as ω/k = c.
An electromagnetic wave in vacuum has an electric field amplitude of Emax = 220 V/m. Calculate the amplitude Bmax of the corresponding magnetic field.
Solution:
The eye is most sensitive to light having a wavelength of 5.5*10-7 m, which is in the green-yellow region of the electromagnetic spectrum. What is the frequency of this light?
Solution:
A plane electromagnetic wave is propagating through
space. In some plane at some time t the fields are uniform and
oriented as shown. What is the direction of propagation of the
plane wave?
Solution:
Plane wave solutions have unphysical properties. They are of infinite
length and the wave fronts have infinite area. Everywhere in an infinite plane
normal to the direction of propagation
E(t) and B(t) are the same. So for a sinusoidal plane
wave propagating along the z-direction we have
E(r,t) = |E0|cos(kz - ωt + φ),
i.e. E only varies along the z-direction, and not along any direction in
the xy plane.
Click here for an attempt to visualize the electric field of a plane wave
propagating along the z-direction in three dimensions.
There are many situations where waves exist that are experimentally
indistinguishable from plane waves. This is the case when the length of
the wave and the width area of the wave front is large compared to the
wavelength of the wave.
AI Study Tip:
Use AI to identify "conceptual gaps." If you understand the math but
not the physical "why," ask the AI to explain the bridge between the wave model
and the ray model.
Example Prompt: 'I am studying Module 1 of a Modern Optics course. I
understand Maxwell’s equations in vacuum, but I’m struggling to visualize how
'rays' emerge from wave equations. Act as a Socratic tutor. Don't
give me the full answer immediately. Instead, ask me a series of questions
to help me derive the relationship between wave fronts and light rays myself.'