Polarization

Light is an electromagnetic wave.  The electric field of a light wave propagating in the z-direction is given by E = E0exp(i(kz - ωt)).  The time-averaged intensity of the wave is (1/(2μ0c))|E0|2.  Light is a transverse wave.  E is a vector lying in the plane perpendicular to z,  E = (Ex, Ey).  Polarized light is produced when the direction of E in the plane perpendicular to the direction of propagation is constrained in some fashion.

The electric field vector E can always be resolved into two perpendicular components.  The light is elliptically polarized when the two components have a constant phase difference, and the tip of the electric field vector traces out an ellipse in the plane perpendicular to the direction of propagation. 

Ex = E0xexp(i(kz - ωt)),  Ey = E0yexp(i(kz - ωt + φ)). 

Linearly polarized light is a special case of elliptically polarized light.  If the light is linearly polarized, then the two components oscillate in phase, for example
Ex = E0xexp(i(kz - ωt)), Ey = E0yexp(i(kz - ωt)), φ = 0. 
The electric vector traces out a straight line in a plane perpendicular to the direction of propagation of the wave. 
For example, E = Ei = E0xexp(i(kz - ωt))i.

imageCircularly polarized light is also a special case of elliptically polarized light, in which E0x = E0y, and the two components have a 90° phase difference.  The electric field vector then traces out a circle in the plane perpendicular to the direction of propagation.  When viewed looking towards the source, a right circularly polarized beam has a field vector that describes a clockwise circle (φ = -π/2), while left circularly polarized light has a field vector that describes a counter-clockwise circle (φ = π/2) at a fixed position z.

The figure below shows the trace of the field vector Ex = E0cos(kz - ωt), Ey = E0cos(kz - ωt + φ) in a plane perpendicular to the z-axis when looking towards the source.  (E0x = E0y = E0).

image image image image
φ = 0
Ex = cos(ωt)
Ey = cos(ωt)
φ = π/4
Ex = cos(ωt)
Ey = cos(ωt - π/4)
φ = π/2
Ex = cos(ωt)
Ey = cos(ωt - π/2)
= sin(ωt)
φ = 3π/4
Ex = cos(ωt)
Ey = cos(ωt - 3π/2)
image image image image
φ = π
Ex = cos(ωt)
Ey = cos(ωt - π)
= -cos(ωt)
φ = 5π/4
Ex = cos(ωt)
Ey = cos(ωt - 5π/4)
φ = 3π/2
Ex = cos(ωt)
Ey = cos(ωt - 3π/2)
= -sin(ωt)
φ = 7π/4
Ex = cos(ωt)
Ey = cos(ωt - 7π/4)

You can also open this Excel spreadsheet and explore.
It contains a macro, so you must download it to run it.


Summary:
Ex = E0xexp(i(kz - ωt)),
Ey = E0yexp(i(kz - ωt + φ)). 

Natural light is, in general, unpolarized.
image


AI Study Tip:
Example Prompt:  'Explain the difference between linear, circular, and elliptical polarization using an analogy involving a person shaking a rope tied to a wall.  How does the 'phase shift' between the horizontal and vertical components translate to the motion of the rope?  Create a table comparing the math (E-field equations) to the physical rope analogy.'