Light is an electromagnetic wave. The electric field of a light wave propagating in the z-direction is given by E = E0exp(i(kz - ωt)). The time-averaged intensity of the wave is (1/(2μ0c))|E0|2. Light is a transverse wave. E is a vector lying in the plane perpendicular to z, E = (Ex, Ey). Polarized light is produced when the direction of E in the plane perpendicular to the direction of propagation is constrained in some fashion.
The electric field vector E can always be resolved into two perpendicular components. The light is elliptically polarized when the two components have a constant phase difference, and the tip of the electric field vector traces out an ellipse in the plane perpendicular to the direction of propagation.
Ex = E0xexp(i(kz - ωt)), Ey = E0yexp(i(kz - ωt + φ)).
Linearly polarized light is a special case of elliptically polarized light.
If the light is linearly polarized, then the two
components oscillate in phase, for example
Ex = E0xexp(i(kz - ωt)),
Ey = E0yexp(i(kz - ωt)), φ
= 0.
The electric vector traces out a
straight line in a plane perpendicular to the direction of propagation of the
wave.
For example, E = Ei = E0xexp(i(kz -
ωt))i.
Circularly polarized light is also a special case of elliptically polarized light,
in which E0x = E0y, and the two components have a 90° phase
difference. The electric field vector then traces out a circle in the plane
perpendicular to the direction of propagation. When viewed looking towards
the source, a right circularly polarized beam has a field vector that describes
a clockwise circle (φ = -π/2), while left
circularly polarized light has a field vector that describes a counter-clockwise circle
(φ = π/2) at a fixed position z.
The figure below shows the trace of the field vector Ex = E0cos(kz - ωt), Ey = E0cos(kz - ωt + φ) in a plane perpendicular to the z-axis when looking towards the source. (E0x = E0y = E0).
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| φ = 0 Ex = cos(ωt) Ey = cos(ωt) |
φ = π/4 Ex = cos(ωt) Ey = cos(ωt - π/4) |
φ = π/2 Ex = cos(ωt) Ey = cos(ωt - π/2) = sin(ωt) |
φ = 3π/4 Ex = cos(ωt) Ey = cos(ωt - 3π/2) |
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| φ = π Ex = cos(ωt) Ey = cos(ωt - π) = -cos(ωt) |
φ = 5π/4 Ex = cos(ωt) Ey = cos(ωt - 5π/4) |
φ = 3π/2 Ex = cos(ωt) Ey = cos(ωt - 3π/2) = -sin(ωt) |
φ = 7π/4 Ex = cos(ωt) Ey = cos(ωt - 7π/4) |
You can also open this Excel
spreadsheet
and explore.
It contains a macro, so you must download it to run it.
Natural light is, in general, unpolarized.

AI Study Tip:
Example Prompt: 'Explain the difference between linear, circular,
and elliptical polarization using an analogy involving a person shaking a rope
tied to a wall. How does the 'phase shift' between the horizontal and
vertical components translate to the motion of the rope? Create a table
comparing the math (E-field equations) to the physical rope analogy.'